2x^2+16x-144=24

Solution for 2x^2+16x-144=24 equation:

2x^2+16x-144=24

We move all terms to the left:

2x^2+16x-144-(24)=0

We add all the numbers together, and all the variables

2x^2+16x-168=0

a = 2; b = 16; c = -168;
Δ = b2-4ac
Δ = 162-4·2·(-168)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-40}{2*2}=\frac{-56}{4}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+40}{2*2}=\frac{24}{4}
=6
$